Hint

The first letter of each term is moved one step forward, the second letter is moved four steps backward and the third letter is moved four steps forward to obtain the corresponding letters of the next term.

Hint

C is the 3rd letter, F sixth, I ninth so next letter will be 12th, i.e. L.
The middle numerics are the squares of 2, 3, 4 and so on. So next numeric would be 25.
The last letter follow the order : U is 3rd letter after R, X is 3rd after U. So, R would be 3rd letter after ‘O’.
∴ Missing term = L25O.

Hint

The letters in the first, second, third and fourth terms are respectively moved one, two, three and four steps forward to obtain the letter in the subsequent terms. the sequence followed by the numbers is +3, +5, +7, +9.

Hint

C is the 3rd letter, F sixth, I ninth so next letter will be 12th, i.e. L.
The middle numerics are the squares of 2, 3, 4 and so on. So next numeric would be 25.
The last letter follow the order : U is 3rd letter after R, X is 3rd after U. So, R would be 3rd letter after ‘O’.
∴ Missing term = L25O.

Hint

The first letter of each term is moved three steps forward and the second letter is moved three steps backward to obtain the corresponding letters of the next term.

Hint

Hint

Observe the first letter of each group. These letters are alternate letters starting from A. Hence, the first letter of the missing group will be G. Similarly, observe second and third letters of each group. Hence, the required group is GWH.

Hint

The first letters in odd numbered terms form series J, I, H and in even numbered terms form the series K, L, M. The sequence followed by the numbers is + 2, + 3, + 4, + 5, + 6. The third letter of each term is moved two steps backward to obtain the third letter of the next term.

Hint

The first letters in odd numbered terms form series J, I, H and in even numbered terms form the series K, L, M. The sequence followed by the numbers is + 2, + 3, + 4, + 5, + 6. The third letter of each term is moved two steps backward to obtain the third letter of the next term.

Hint

The first letter of each term is moved three steps forward and the last letter is moved two steps backward to obtain the corresponding letters of the next term. The numbers follow the sequence:
× 2 + 1, × 2 + 2, × 2 + 3, × 2 + 4.
So, 10 is wrong and must be replaced by:
(4 × 2 + 1) i.e. 9.

Hint

a a b b / b b a a / a a b b / b b a a.

Hint

baab/baab/baab

Hint

cabbac/cabbac/cabbac.

Hint

a a b b c c d d / a a a b b b c c c d d d

Hint

The series is abc/aabc/aabbc/aabbcc/a.

Hint

The series is babb/bbab/bbba/bbbb.
Thus, in each sequence, ‘a’ moves one step forward and ‘b’ takes its place and finally in the fourth sequence, it is eliminated.

Hint

baab/baab/baab

Hint

cabbac/cabbac/cabbac.

Hint

The series is abc/aabc/aabbc/aabbcc/a.

Hint

The series is babb/bbab/bbba/bbbb.
Thus, in each sequence, ‘a’ moves one step forward and ‘b’ takes its place and finally in the fourth sequence, it is eliminated.

Hint

(Q.1-5): Here it is case of arrangement. The logic is: the words get arranged in alphabetical order. Whereas the numbers get arranged in descending order. Numbers occupy odd places in the final steps while words occupy even positions. When any element gets arranged the previous elements occupying that position shifts one place towards right.
Input: 9 13 about tariff 24 call 29 even
Step I: 29 9 13 about tariff 24 call even
Step II: 29 about 9 13 tariff 24 call even
Step III: 29 about 24 9 13 tariff call even
Step IV: 29 about 24 call 9 13 tariff even

Hint

(Q.1-5): Here it is case of arrangement. The logic is: the words get arranged in alphabetical order. Whereas the numbers get arranged in descending order. Numbers occupy odd places in the final steps while words occupy even positions. When any element gets arranged the previous elements occupying that position shifts one place towards right.
Step II: 37 desk 34 garden 5 father victory 17
Step III: 37 desk 34 father garden 5 victory 17
Step IV: 37 desk 34 father 17 garden 5 victory
Since all the elements of the input are fully arranged in Step IV, this is the last step of the given input.

Hint

Here it is case of arrangement. The logic is: the words get arranged in alphabetical order. Whereas the numbers get arranged in descending order. Numbers occupy odd places in the final steps while words occupy even positions. When any element gets arranged the previous elements occupying that position shifts one place towards right.
Step I: 59 bead tenure father 38 11 ultimate 24
Step II: 59 bead 38 tenure father 11 ultimate 24
Step III:59 bead 38 father tenure 11 ultimate 24

Hint

Since it is a case of arrangement, we can’t obtain previous steps with certainty.

Hint

Hint

Since it is a case of arrangement, therefore previous steps or input can’t be determined with certainty.

Hint

(Q. 6-10): An intuitive look at the input and the steps makes it clear that it is a case of arrangement. The input is a combination of words and numbers. Words get arranged according to reverse order of alphabetical arrangement whereas numbers get arranged in ascending order.
In step I, ‘over’ occupies the first place from the left end and the other elements are pushed one place rightward. Similarly, in step II, ‘26’ occupies the second place from the left end and the other elements are pushed one place rightward. Thus, alternate arranging of words and numbers finally gives the last step in which the odd places from the left are occupied by words and the even places are occupied by numbers.
Step III: take 17 mind game 29 73 18 loud
Step IV: take 17 mind 18 game 29 73 loud
Step V: take 17 mind 18 loud game 29 73
Step VI: take 17 mind 18 loud 29 game 73
Hence, step VI is the last step. Therefore, three more steps are required to complete the sequence.

Hint

An intuitive look at the input and the steps makes it clear that it is a case of arrangement. The input is a combination of words and numbers. Words get arranged according to reverse order of alphabetical arrangement whereas numbers get arranged in ascending order.
In step I, ‘over’ occupies the first place from the left end and the other elements are pushed one place rightward. Similarly, in step II, ‘26’ occupies the second place from the left end and the other elements are pushed one place rightward. Thus, alternate arranging of words and numbers finally gives the last step in which the odd places from the left are occupied by words and the even places are occupied by numbers.
Input: by now 51 32 for 91 20 me
Step I: now by 51 32 for 9120 me
Step II: now 20 by 51 32 for 91 me
Step III: now 20 me by 51 32 for 91
Step IV: now 20 me 32 by 51 for 91
Step V: now 20 me 32 for by 51 91
Step VI: now 20 me 32 for 51 by 91
Hence, step VI is the last step for the giveninput.

Hint

An intuitive look at the input and the steps makes it clear that it is a case of arrangement. The input is a combination of words and numbers. Words get arranged according to reverse order of alphabetical arrangement whereas numbers get arranged in ascending order.
In step I, ‘over’ occupies the first place from the left end and the other elements are pushed one place rightward. Similarly, in step II, ‘26’ occupies the second place from the left end and the other elements are pushed one place rightward. Thus, alternate arranging of words and numbers finally gives the last step in which the odd places from the left are occupied by words and the even places are occupied by numbers.
Input: queen mary 79 62 17 20 green west
Step I: west queen mary 7962 1720 green
Step II: west 17 queen mary 79 62 20 green
Step III: west 17 queen 20 mary 79 62 green
Step IV: west 17 queen 20 mary 62 79 green
Step V: west 17 queen 20 mary 62 green 79
Hence, step V is the last step. Therefore, the penultimate step (last but one) is step IV.